Ravens Rookie Earns Defensive Player of the Week Honors
Baltimore Ravens rookie first-round pick Odafe Oweh in just his second career game, was named AFC defensive player of the week.
Oweh was a dominant force for the Ravens on Sunday night against the Kansas City Chiefs. Oweh recorded three tackles on the night, and made two key plays that both times shifted momentum in the Ravens favor.
The Chiefs faced a third and long on their own 49-yard line with a 35-24 lead with 2:09 remaining in the third quarter. The Ravens desperately needed a stop to give the ball back to Lamar Jackson and the Ravens offense. Chiefs quarterback Patrick Mahomes dropped back to pass stepping up into the pocket. Oweh ripped through his block wrapping Mahomes up around the legs. As Mahomes fell to the ground he threw a high wobbly pass into the waiting arms of Ravens cornerback Tavon Young. The Ravens would eventually go on a 14 play 68-yard drive to cut the lead to 35-30 following the interception.
But the biggest play in Oweh’s young career came late in the fourth quarter. After the Ravens scored to take a 36-35 lead with 3:18 remaining in the fourth quarter, Mahomes and the Chiefs quickly moved down the field taking just three plays to move into Ravens territory. On second down from the Ravens 32-yard line, the Chiefs handed it off to running back Clyde Edwards-Helaire. Oweh rushed through the middle and with a blocker on his back punched the ball out of the left arm of Edwards-Helaire. A scrum for the ball ensued with Oweh coming out of the pile recovering his own forced fumble. The Ravens would convert on a fourth down on their following offensive possession to seal the Ravens thrilling victory.
Oweh recorded his first career sack against the Las Vegas Raiders in week one, and now his first career forced fumble leading to an enormous Ravens win. Oweh has shown early why he was picked in the first round and will look to build on his quick start as the season goes on.